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iLQR

Dependencies

vehicle control example

image image

Usage

from ilqr import iLQR
from ilqr.containers import Dynamics, Cost

See examples folder for more insight on how to use this repo.

Construting Dynamics

Let’s consider a simple problem i.e. pushing a box to goal position from start (double integrator system). The dynamics are defined as

s" = u/mass

Finite Diff Dynamics

Partial derivatives are computed using Finite Difference approximation.

import numpy as np
from ilqr.containers import Dynamics

# params
m  = 2.0 # mass
dt = 0.1 # discrete time step
#numerical function
def f(x, u):
  #velocity
  vel = x[1]
  #acceleration
  acc = u[0]/m
  #construct state_dot
  x_dot  = np.array([vel, acc])
  return x_dot

#contruct Dynamics
dynamics = Dynamics.Continuous(f, dt)

Symbolic Dynamics

Partial derivatives are computed symbolically using sympy and compiled with Numba.

import sympy as sp
from ilqr.utils import GetSyms
from ilqr.containers import Dynamics

#state and action dimensions
n_x = 2
n_u = 1

#params
m  = 2.0
dt = 0.1
#Get Symbolic variables
x, u = GetSyms(n_x, n_u)
#Construct Discrete dynamics
x_n  = x + sp.Matrix([x[1], u[0]/m])*dt
dynamics = Dynamics.SymDiscrete(x_n, x, u)

Note: You can also directly construct dynamics by hard coding the partial derivaties and wrapping them with numba.jit decorator.

def f(x, u): ...
def f_x(x, u): ...
def f_u(x, u): ...
dynamics = Dynamics(f, f_x, f_u)

usage

>>> dynamics.f(x0, u0)
>>> dynamics.f_x(x0, u0)
>>> dynamics.f_u(x0, u0)

Construting Cost

Let’s construct a simple cost to penalise the box for staying away from goal (i.e S = 10m).

Simple cost

import sympy as sp
from ilqr.utils import GetSyms
from ilqr.containers import Cost

x, u = GetSyms(n_x, n_u)

#displacement and velocity
s, v = x
#Terminal cost
Lf = 10*(s - 10)**2
#Running cost
L = (s - 10)**2 + 0.1*v**2 + 0.1*u[0]**2
#construct cost
cost = Cost.Symbolic(L, Lf, x, u)

Note: Currently only Symbolic costs are supported

Constrain control input or state variable

from ilqr.utils import Bounded

L = (s - 10)**2 + 0.1*v**2
#Running cost with constraint on applied force (2N to -2N)
L += Bounded(u, high = [2], low = [-2])
#construct cost
cost = Cost.Symbolic(L, Lf, x, u)

Quadratic Cost

import numpy as np
import sympy as sp
from ilqr.utils import GetSyms, Bounded
from ilqr.containers import Cost

x_goal = np.array([10, 0])
Q  = np.diag([1, 0.1])
R  = np.diag([0.1])
QT = np.diag([10, 10])
#construct Quadratic Cost
cost = Cost.QR(Q, R, QT, x_goal)

#Add constraints on Force (2N to -2N)
cons = Bounded(u, high = [2], low = [-2])
#construct Quadratic cost with constraints
cost = Cost.QR(Q, R, QT, x_goal, cons)

usage

>>> cost.L(x0, u0)
>>> cost.L_x(x0, u0)
>>> cost.L_ux(x0, u0)
    .
    .
>>> cost.Lf(x0)
>>> cost.Lf_xx(x0)

iLQR

from ilqr import iLQR

controller = iLQR(dynamics, cost)

#initial state
x0 = np.array([0, 0])
#initil guess
us_init = np.random.randn(N, n_u)*0.01
#run optimization
xs, us, cost_trace = controller.fit(x0, us_init)

Note: The first run is slower since numba has to compile the functions. Some parameters of iLQR controller can customised as per your needs (Look at the code for more info)

Let’s look at the results

Displacement and Force applied with out constraint on force. image

Displacement and Force applied with constraint on force. image

You can see that the force does not cross the 2N limit.

MPC

from ilqr.controller import MPC

mpc = MPC(controller, control_horizon = 1)

#initial state
x0 = np.array([0, 0])

#Prediction Horizon
N = 50
#Initil guess
us_init = np.random.randn(N, n_u)*0.01
mpc.set_initial(us_init)

#get optimal action
us = mpc.control(x0)
#after observing next state
us = mpc.control(x_next)

Future Work

References